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太简单还有这么多人不过,无语,其实我也是个菜鸟……

Posted by visual at 2006-04-13 14:18:03 on Problem 1658
#include<iostream>
using namespace std;

int main()
{
    long a[4];
    int n;
    long  d;
    cin>>n;
    for(int i =1; i<=n; i++)
    {
     cin>>a[0]>>a[1]>>a[2]>>a[3];
     if((a[1]-a[0]==a[2]-a[1])&&(a[3]-a[2]==a[2]-a[1])) 
      cout<<a[0]<<" "<<a[1]<<" "<<a[2]<<" "<<a[3]<<" "<<a[3]+a[2]-a[1]<<endl;
     else
     
       cout<<a[0]<<" "<<a[1]<<" "<<a[2]<<" "<<a[3]<<" "<<a[3]*a[1]/a[0]<<endl;
     }
      
    
}

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