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太简单还有这么多人不过,无语,其实我也是个菜鸟……#include<iostream>
using namespace std;
int main()
{
long a[4];
int n;
long d;
cin>>n;
for(int i =1; i<=n; i++)
{
cin>>a[0]>>a[1]>>a[2]>>a[3];
if((a[1]-a[0]==a[2]-a[1])&&(a[3]-a[2]==a[2]-a[1]))
cout<<a[0]<<" "<<a[1]<<" "<<a[2]<<" "<<a[3]<<" "<<a[3]+a[2]-a[1]<<endl;
else
cout<<a[0]<<" "<<a[1]<<" "<<a[2]<<" "<<a[3]<<" "<<a[3]*a[1]/a[0]<<endl;
}
}
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