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太简单还有这么多人不过,无语,其实我也是个菜鸟……#include<iostream> using namespace std; int main() { long a[4]; int n; long d; cin>>n; for(int i =1; i<=n; i++) { cin>>a[0]>>a[1]>>a[2]>>a[3]; if((a[1]-a[0]==a[2]-a[1])&&(a[3]-a[2]==a[2]-a[1])) cout<<a[0]<<" "<<a[1]<<" "<<a[2]<<" "<<a[3]<<" "<<a[3]+a[2]-a[1]<<endl; else cout<<a[0]<<" "<<a[1]<<" "<<a[2]<<" "<<a[3]<<" "<<a[3]*a[1]/a[0]<<endl; } } Followed by:
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