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什么公式阿我忘光了几何

Posted by xiaxia at 2006-04-10 23:55:08 on Problem 2812
In Reply To:有个公式的，不用考虑那种情况 Posted by:Sempr at 2006-04-10 23:50:07

Followed by:

S = 0.5*Sum(p[i].x * p[(i+1)%N].y - p[i].y*p[(i+1)%N].x) (7) Sempr 2006-04-11 07:10:01
- 看懂了应该是利用向量的，怎么证明的哈？ (9) first 2006-04-11 12:55:04
  - 曲线的定积分 (0) qywyh_scut 2006-05-07 10:47:51
    - 曲线定积分?? 没这么高深吧,叉乘而已 (0) nobody_is_me 2006-11-01 17:30:36
  - Re:看懂了应该是利用向量的，怎么证明的哈？ (7) bobobo 2007-08-20 18:36:22
- 很好的公式。。。。 (9) scauben0 2006-05-06 22:34:56

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