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有个公式的，不用考虑那种情况

Posted by Sempr at 2006-04-10 23:50:07 on Problem 2812
In Reply To:凹边形怎么处理呢 Posted by:xiaxia at 2006-04-10 23:15:24

Followed by:

什么公式阿我忘光了几何 (0) xiaxia 2006-04-10 23:55:08
- S = 0.5*Sum(p[i].x * p[(i+1)%N].y - p[i].y*p[(i+1)%N].x) (7) Sempr 2006-04-11 07:10:01
  - 看懂了应该是利用向量的，怎么证明的哈？ (9) first 2006-04-11 12:55:04
    - 曲线的定积分 (0) qywyh_scut 2006-05-07 10:47:51
      - 曲线定积分?? 没这么高深吧,叉乘而已 (0) nobody_is_me 2006-11-01 17:30:36
    - Re:看懂了应该是利用向量的，怎么证明的哈？ (7) bobobo 2007-08-20 18:36:22
  - 很好的公式。。。。 (9) scauben0 2006-05-06 22:34:56

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