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Re:现在把程序精简一下,却变成Runtime Error!感觉还是细节没有考虑到,请指教In Reply To:现在把程序精简一下,却变成Runtime Error!感觉还是细节没有考虑到,请指教 Posted by:xiaoxiaodi at 2006-01-11 22:51:44 > #include<stdio.h>
> #include<string.h>
> char haab[19][10]={"pop","no","zip","zotz","tzec","xul","yoxkin","mol","chen","yax","zac","ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"};
> char tz[20][10]={"imix","ik","akbal","kan","chicchan","cimi","manik","lamat","muluk","ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau"};
> void main()
> {
>
> int num,year,n,i=0,j=0,k=0,flag=0,sum=0;
> char s[10];
> scanf("%d",&n);
> while(i<n)
> {
> scanf("%d.",&num);
> scanf("%s",s);
> scanf("%d",&year);
> if(year>=5000 || year<0) return;
> while(flag!=1)
> {
> while((haab[k][0]!=s[0]))
> {
> k++;
> }
> while(haab[k][j]==s[j])
> {
> j++;
> }
> k++;
> if(haab[k-1][j]=='\0') flag++;
> else continue;
> }
> if(k>19) return;
> if(k==19)
> {
> if(num<0 || num>4) return;
> }
> else
> {
> if(num<0 || num>19) return;
> }
> sum = year*365+(k-1)*20+num;
> printf("%d %s %d\n",1+sum%13,tz[sum%20],sum/260);
> i++;
> k=0;
> flag=0;
> j=0;
> }
> }
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