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Re:现在把程序精简一下,却变成Runtime Error!感觉还是细节没有考虑到,请指教

Posted by wyqt at 2006-04-09 17:25:16 on Problem 1008
In Reply To:现在把程序精简一下,却变成Runtime Error!感觉还是细节没有考虑到,请指教 Posted by:xiaoxiaodi at 2006-01-11 22:51:44
> #include<stdio.h>
> #include<string.h>
> char haab[19][10]={"pop","no","zip","zotz","tzec","xul","yoxkin","mol","chen","yax","zac","ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"};
> char tz[20][10]={"imix","ik","akbal","kan","chicchan","cimi","manik","lamat","muluk","ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau"};
> void main()
> {
> 	
> 	int num,year,n,i=0,j=0,k=0,flag=0,sum=0;
> 	char s[10];
> 	scanf("%d",&n);
>     while(i<n)
> 	{
> 		scanf("%d.",&num);
> 		scanf("%s",s);
> 		scanf("%d",&year);
> 		if(year>=5000 || year<0) return;
>         while(flag!=1)
> 		{
> 			while((haab[k][0]!=s[0]))
> 			{
> 				k++;    
> 			}
> 			while(haab[k][j]==s[j])
> 			{
> 				  j++;  
> 			}
> 			k++;
> 			if(haab[k-1][j]=='\0')  flag++;
> 			else continue;
> 		}
> 		if(k>19) return;
> 		if(k==19) 
> 		{
> 			if(num<0 || num>4) return;
> 		}
> 		else
> 		{
> 			if(num<0 || num>19) return;
> 		}
> 		sum = year*365+(k-1)*20+num;  
>         printf("%d %s %d\n",1+sum%13,tz[sum%20],sum/260);
> 		i++;
> 		k=0;
> 		flag=0;
> 		j=0;
> 	}
> }

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