> 你看看我的程序！
> char month2[20][10] ={ "imix ", "ik ", "akbal ", "kan ", "chicchan ", "cimi ", "manik ", "lamat ", "muluk ", "ok ", "chuen ","eb ", "ben ", "ix ", "mem ", "cib ", "caban ", "eznab ", "canac ", "ahau "};
> 这儿按初始数据来的，
> 后来的天数需要+1
> 
> #include <string.h>
> #include <stdio.h> 
> #define NUM_DAY1 365
> #define NUM_DAY2 (13 * 20)
> int main()
> {
> 	char month1[19][9]={"pop", "no","zip","zotz","tzec","xul","yoxkin","mol","chen","yax","zac", "ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"};
> 	char month2[20][10] ={ "imix ", "ik ", "akbal ", "kan ", "chicchan ", "cimi ", "manik ", "lamat ", "muluk ", "ok ", "chuen ","eb ", "ben ", "ix ", "mem ", "cib ", "caban ", "eznab ", "canac ", "ahau "};
> 	int year1,day1,year2,day2,day,n,i,cnt,r;
> 	char t,input[30],month[10],*nameOfDay=(char *)malloc(10*sizeof(char));
> 	scanf("%d",&n);
> 	printf("%d\n",n);
> 	while(n>0){
> 		scanf("%d",&day1);   ////  ?
> 		scanf("%c",&t);      /////?
> 		scanf("%s",month);   ////?
> 		scanf("%d",&year1);  //////? 空格呢 
> 		
> 		//change
> 		for (i=0;strcmp(month,month1[i]);i++);
> 		cnt = year1 * NUM_DAY1 + i * 20 + day1;		
> 		year2 = cnt / NUM_DAY2;
> 		r = cnt % NUM_DAY2;
> 		day2 = r % 13 + 1;
> 		nameOfDay = month2[r % 20];
> 		printf("%d %s%d\n",day2,nameOfDay,year2);
> 		n--;
>  	}
> 	return 0;
> }