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用归排序输入的四个数组排序,两两相加后用归并排序会比快排更快 不信试试看 在处理a+b+c+d=0 可以写作 a + b= - c -d c 和d 的数组取反 这样只要查找 两两数组中相等的就可 查找的核心代码 __int64 cnt = 0; int p1 = 0,p2 = 0; while(p1 < n && p2 < n) { if(n1[p1] > n2[p2]) p2++; else if(n1[p1] < n2[p2]) p1++; else { int c1 = 1,c2 = 1; p1++,p2++; while(n1[p1-1] == n1[p1] && p1++ < n) c1++; while(n2[p2-1] == n2[p2] && p2++ < n) c2++; cnt += c1*c2; } } Followed by:
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