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Re:请问:怎么递归啊?In Reply To:Re:请问:怎么递归啊? Posted by:ggg at 2004-06-03 10:14:49 > x1+x2+x3+....xn=m,x1>=x2>=....>=xn
> 本题等价于求解上述方程的解的个数,令fun[k][n][m]表示x1=k时的个数,则
> for(j=0;j<=m-k&&j<=k;j++)
> {
> fun[k][n][m]+=fun[j][n-1][m-k];
> }
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