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改成stl的sort你的程序wa了In Reply To:Re:ft............ Posted by:sza at 2006-03-25 03:02:29 > 继续超时,哭。。。。。。。。 > > #include <stdio.h> > #include <stdlib.h> > int abs64(int a){ > if(a<0) return -a;else return a; > } > int cmp(const void *i,const void *j){ > return *((const int*)i)-*((const int*)j); > } > int numerate1[7800000],numerate2[7800000],a[4001],b[4001],c[4001],d[4001],tem; > int main(int argc, char *argv[]) > { > long index,i,j,k,m,n,counter=0,head,tail,ch,ct,c1,c2; > scanf("%d",&n); > for(i=0;i<n;i++) scanf("%d %d %d %d",&a[i],&b[i],&c[i],&d[i]); > counter=0; > index=0; > for(i=0;i<n;i++){ > for(j=0;j<n;j++){ > numerate1[index++]=a[i]+b[j]; > } > } > index=0; > for(i=0;i<n;i++){ > for(j=0;j<n;j++){ > numerate2[index++]=c[i]+d[j]; > } > } > qsort(numerate1,index,sizeof(int),cmp); > qsort(numerate2,index,sizeof(int),cmp); printf("ok\n"); > head=0;tail=index-1; > while(head<index && tail>=0){ > c1=1;c2=1; > if(numerate1[head]+numerate2[tail]==0) { > ch=head;ct=tail; > while(head<index && numerate1[ch]==numerate1[++head]) c1++; > while(tail>=0 && numerate2[ct]==numerate2[--tail]) c2++; > counter=counter+c1*c2; > } > else if(numerate1[head]<=0&&numerate2[tail]>=0){ > if(abs64(numerate1[head])<abs64(numerate2[tail])) tail--; > else head++; > } > else if(numerate1[head]>=0&&numerate2[tail]<=0){ > if(abs64(numerate1[head])<abs64(numerate2[tail])) head++; > else tail--; > } > else if(numerate1[head]<=0&&numerate2[tail]<=0){ head++; > } > else if(numerate1[head]>=0&&numerate2[tail]>=0){ tail--; > } > } > printf("%ld\n",counter); > } Followed by:
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