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Re:闰年的处理

Posted by tellit at 2006-03-09 23:18:01 on Problem 2210
In Reply To:闰年的处理 Posted by:szliuxf at 2006-03-08 00:54:37 
应该是
365*(year-2000)+(year-1997)/4-(year-2000)/100+(year-2000)/400;

> 处理 0:0:0 1.1.2100, 看大家的算法好象是错的. 还是我错啦?
> 
> 2000 - 2100 should have 25 leap years.
> 
> total += 365*(year - 2000) + (year - 2000)/4 - (year - 2000)/100 + (year - 2000)/400;
> will give 25 - 1 = 24.
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