| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
一种方法#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
char s1[100000],s2[100000];
int len1,len2;
int i,j;
while(scanf("%s%s",&s1,&s2)==2)
{
len1=strlen(s1);
len2=strlen(s2);
j=0;
for(i=0;i<len1 && j<len2;i++)
{
while(s1[i]!=s2[j++])
;
}
if(i=len1 && j<=len2)
printf("Yes\n");
else
printf("No\n");
}
}
Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator