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Re:通过的代码,看吧,很简单

Posted by hudedi at 2006-01-01 02:05:41 on Problem 1032
In Reply To:通过的代码,看吧,很简单 Posted by:hahaxiao at 2005-09-03 09:08:00
如果你真的有什么心得,可以用几条语句或几条代码表示出来,贴出整个代码不太好
> #include <iostream>
> using namespace std;
> int main() {
> 	int a[1001];
> 	int n;
> 	int i,j;
> 	int sum,r;
> 	while(cin>>n) {
> 		sum=0;
> 		i=2; sum+=i;
> 		while(sum<=n) {
> 			a[i]=i;
> 			++i;
> 			sum+=i;
> 		}
> 		sum=sum-i;
> 		--i;
> 		r=i;
> 		if(sum==n){
> 			cout<<a[2];
> 			for(i=3;i<=r;i++)
> 				cout<<' '<<a[i];
> 		}
> 		else {
> 			for(i=2;i<=r;i++)
> 				if(a[i]+n-sum>a[r]){
> 					a[++r]=a[i]+n-sum;
> 					j=i;
> 					break;
> 				}
> 			if(j==2) {
> 				cout<<a[3];
> 				for(i=4;i<=r;i++)
> 					cout<<' '<<a[i];
> 				cout<<endl;
> 			}
> 			else {
> 				cout<<a[2];
> 				for(i=3;i<j;i++)
> 					cout<<' '<<a[i];
> 				for(i=j+1;i<=r;i++)
> 					cout<<' '<<a[i];
> 				cout<<endl;
> 			}
> 		}
> 	}
> 	return 0;
> }
> 

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