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Re:简单解法：）

Posted by IC0500510080 at 2005-12-25 17:25:15 on Problem 1844
In Reply To:简单解法：） Posted by:IC0500510080 at 2005-12-25 17:25:09

#include<stdio.h>
void main()
{
	int n,k,m;
	scanf("%d",&n);
	for(int i=0;;i++)
	{
		if((i*(i+1)/2)>=n)
		{k=i*(i+1)/2;break;}
	}
	if(k==n)m=i;
	else if((k-n)%2==1&&i%2==1)m=i+2;
	else if((k-n)%2==1&&i%2==0)m=i+1;
	else if((k-n)%2==0)m=i;
	printf("%d\n",m);
}

Followed by:

切，比我的还长 (308) frkstyc 2005-12-25 17:32:20
更简单的 (139) yiyiyi4321 2006-07-31 16:51:04

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