#include <stdio.h>
#define BIT(x, n) (((x) >> (n)) & 1u)
#define BIT1(n) (1u << (n))
#define SET(x, n, b) (((x) & ~BIT1(n)) | ((b) << (n)))
#define MASK(n, m) (((1u << (m)) - 1) << (n))
#define ROR(x, n, m) (((x) & ~MASK(n, m)) | (BIT(x, n) << ((n) + (m) - 1)) | (((x) & MASK((n) + 1, (m) - 1)) >> 1))
#define ADD(x) \
	do\
	{\
		(x) = ROR(x, 0, 8);\
		(x) = ROR(x, 16, 8);\
		(x) = SET(x, 25, (BIT(x, 7) & BIT(x, 23)) | (BIT(x, 7) & BIT(x, 24)) | (BIT(x, 23) & BIT(x, 24)));\
		(x) = SET(x, 7, BIT(x, 7) ^ BIT(x, 23) ^ BIT(x, 24));\
		(x) = SET(x, 24, BIT(x, 25));\
	}\
	while(0)
#define ADD8(x) \
	do\
	{\
		ADD(x);\
		ADD(x);\
		ADD(x);\
		ADD(x);\
		ADD(x);\
		ADD(x);\
		ADD(x);\
		ADD(x);\
	}\
	while(0)

int main(void)
{
	unsigned int a;
	scanf("%hu %hu", (unsigned short int*)&a, (unsigned short int*)&a + 1);
	ADD8(a);
	printf("%u\n", (unsigned int)*(unsigned char*)&a);
	return 0;
}

• Re:狂fight (1007) kansas 2005-12-17 21:45:38
  • 和8位加法电路的原理差不多 (0) frkstyc 2005-12-17 22:36:51
• 真牛，赞，应该推选为1000的标程 (1007) KOPOPT 2005-12-17 23:00:44
• 牛。。。 (1007) wywcgs 2005-12-17 23:40:10