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me tooIn Reply To:在某个状态,取出下次访问时间最晚的元素,替换 Posted by:zymx at 2005-10-30 16:54:46 #include <stdio.h>
int main() {
int i,j,k,n,t,p,q,max;
int driver[11];
int req[101];
int insert;
scanf("%d",&t);
for(;t>0;t--){//case number
scanf("%d%d",&k,&n);
if(k>=n) {//driver number biger or equal than dvd
for(i=0;i<n;i++){
scanf("%d",&j);
}
printf("%d\n",n);
continue;
}
for(i=0;i<n;i++){
scanf("%d",&req[i]);
}
for(i=0;i<k;i++){
driver[i]=req[i];
}
insert=k; //there should be at least k insertions
for(i=k;i<n;i++){
for(j=0;j<k;j++){
if(req[i]==driver[j])break;
}
if(j<k)continue; //needn't to insert
max=-1;
for(j=0;j<k;j++) {
for(p=i+1;p<n;p++) {
if(driver[j]==req[p])break;
}
if(max<p){ //find the last that need to insert
max=p;
q=j;
}
}
++insert;
driver[q]=req[i];
}
printf("%d\n",insert);
}
return 0;
}
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