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没看到有memory limit exceed的啊In Reply To:搞了半天,又是run time error 又是 memory limited 我深感绝望,谁来帮帮我(附代码) Posted by:ggg at 2004-04-24 02:49:36 > #include<iostream.h> > long a[101][101]; > int leng[101][101]; > int n,c; > int len(int,int); > int main() > { > int i;int j; > > while( cin>>n>>c) > { > for( i=1;i<=n;i++) > for( j=1;j<=c;j++) > { > cin>>a[i][j]; > leng[i][j]=-1; > } > for(i=0;i<=c+1;i++) > a[0][i]=-2; > for(i=0;i<=c+1;i++) > a[n+1][i]=-2; > for(j=0;j<=n+1;j++) > a[j][0]=-2; > for(j=0;j<=n+1;j++) > a[j][n+1]=-2; > > int max=-1; > for(int u=1;u<=n;u++) > for(int v=1;v<=c;v++) > { > if(leng[u][v]!=-1) > { > if(leng[u][v]>max) > max=leng[u][v]; > } > else > { > if(len(u,v)>max) > max=leng[u][v]; > } > } > cout<<max<<endl; > } > return 0; > } > > int len(int u,int v) > { > > > if(leng[u][v]!=-1) > return leng[u][v]; > int m=1; > if(a[u][v]>=a[u-1][v]&&a[u-1][v]!=-2&&len(u-1,v)+1>m) > { > m=1+leng[u-1][v]; > } > if(a[u][v]>=a[u+1][v]&&a[u+1][v]!=-2&&len(u+1,v)+1>m) > { > m=1+leng[u+1][v]; > } > if(a[u][v]>=a[u][v-1]&&a[u][v-1]!=-2&&len(u,v-1)+1>m) > { > m=1+leng[u][v-1]; > } > > if(a[u][v]>=a[u][v+1]&&a[u][v+1]!=-2&&len(u,v+1)+1>m) > { > m=1+leng[u][v+1]; > } > leng[u][v]=m; > return m; > > > } Followed by: Post your reply here: |
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