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Re:大侠们! 指导一下小弟吧!我用的算法依然是排序加回溯,但都超时了N次了。(附上程序)In Reply To:大侠们! 指导一下小弟吧!我用的算法依然是排序加回溯,但都超时了N次了。(附上程序) Posted by:team7 at 2005-11-03 21:41:54 > #include "stdio.h"
> #include "stdlib.h“
>
> void bol(int a[],int T)
> {
> int i,j,change,t;
> for(i=T-1,change=1;i>=1&&change;i--)
> {
> change=0;
> for(j=0;j<i;j++)
> {
> if(a[j]<a[j+1])
> {
> t=a[j];
> a[j]=a[j+1];
> a[j+1]=t;
> change=1;
> }
> }
> }
> }
>
> int T;
> int huisu(int k,int b[],int a[]);
>
> int main()
> {
> int i,k,b[70];
> int num,a[70],sum,n,n2;
> scanf("%d",&T);
> while(T)
> {
> num=0;
> sum=0;
> n2=0;
> for(i=0;i<T;i++)
> {
> scanf("%d",&a[i]);
> if(a[i]>50) {a[i]=0;n2++;}
> sum+=a[i];
> }
> bol(a,T);
>
> if(a[0]==0) {printf("0\n");continue;}
> k=sum/a[0];
> printf("%d\n",a[0]);
> for(;k>=1;k--)
> {
> if(sum%k==0)
> {
> n=sum/k;
> if(a[k]+a[k-1]>n) continue;
> for(i=0;i<k;i++)
> {
> b[i]=n;
>
> }
> num=huisu(k,b,a);
> }
> if(num==1) break;
> }
> printf("%d\n",sum/k);
>
> scanf("%d",&T);
> }
> return 0;
> }
>
> int huisu(int k,int b[],int a[])
> {
> int i,j;
> int n,m,num;
> int flag;
> n=0;
> m=0;
>
> for(i=0;i<k;i++)
> {
>
> if(b[i]!=0)
> {
> for(j=0;j<T;j++)
> {
>
> flag=0;
> if(a[j]==m) continue;
>
> if(a[j]!=0&&a[j]<=b[i])
> {
>
> n=b[i];
> flag=1;
> b[i]=b[i]-a[j];
> m=a[j];
> a[j]=0;
> if(i==(k-1)&&b[i]==0)
> return 1;
> else
> num=huisu(k,b,a);
> }
> if(flag==1)
> {
> if(num==1) return 1;
> else {b[i]=n;a[j]=m;}
> }
>
> }
> if(b[i]!=0) return 0;
> }
> }
> return 0;
> }
你是WA,必须用回溯吗?请问先排序,再从大到小拼,为什么不行呢?
1 1 1 2 2 2 5 5 5 就从5开始,前三个可以,6-5-1, 6-5-1, 6-5-1
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