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水题!最抽象的一件事是我交代码的时候,没删一行测试输出,为此还找了老师#include <iostream> #include <cstring> using namespace std; string a, b; int main(){ cin >> a >> b; long long sum = 0; // cout << a.size()<< ' ' << b.size() << endl; // 最抽象的一件事是我交代码的时候,没删这行测试输出 // 为此还找了老师 for(int i = 0; i < a.size(); ++i){ for(int j = 0; j < b.size(); ++j){ // cout << (int)(a[i] - '0') << ' ' << (int)(b[j] - '0') << endl; sum += (int)(a[i] - '0') * (int)(b[j] - '0'); } } cout << sum << endl; return 0; } Followed by:
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