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水题!最抽象的一件事是我交代码的时候,没删一行测试输出,为此还找了老师#include <iostream>
#include <cstring>
using namespace std;
string a, b;
int main(){
cin >> a >> b;
long long sum = 0;
// cout << a.size()<< ' ' << b.size() << endl;
// 最抽象的一件事是我交代码的时候,没删这行测试输出
// 为此还找了老师
for(int i = 0; i < a.size(); ++i){
for(int j = 0; j < b.size(); ++j){
// cout << (int)(a[i] - '0') << ' ' << (int)(b[j] - '0') << endl;
sum += (int)(a[i] - '0') * (int)(b[j] - '0');
}
}
cout << sum << endl;
return 0;
}
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