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对于解的构造，把一个开头为负的后面跟着一连串为正的作为一个单元，那么这个结果就是该对应的数字序列从头到尾相减的结果In Reply To:可以用背包算法来枚举后面数字的正负号，即可得是否有解 Posted by:yygy at 2023-05-12 09:37:34 Followed by: Post your reply here: |
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