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可以用背包算法来枚举后面数字的正负号，即可得是否有解In Reply To:把表达 式展开之后，除了a0,a1前面是固定的除号，后面的数字前面前面正可负，总共有2^（n-1）种形式， Posted by:yygy at 2023-05-12 09:37:13 Followed by:
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