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超级简洁的代码

Posted by Ioencgc at 2023-04-05 19:36:14 on Problem 1631
#include<iostream>
#include<stack>
#include<string.h>
#include<cmath>
#include<iomanip>
#include<algorithm>
#include<climits>
#include<cstdio>
#include<vector>
#include<sstream>
#include<ctype.h>
#include<set>
#include<map>
#include<ctime>
#include<stdlib.h>
#include<queue>
#include<bitset>
#define usi unsigned int
#define ull unsigned long long
using namespace std;
template<typename TTT>inline void mr(TTT& theNumberToRead)
{
	theNumberToRead = 0;
	bool prn = false;
	char c = getchar();
	while (!isdigit(c))
	{
		if (c == '-')prn = true;
		c = getchar();
	}
	while (isdigit(c))
		theNumberToRead = 10 * theNumberToRead + (c ^ 48), c = getchar();
	if (prn)
		theNumberToRead = -theNumberToRead;
}
template<typename TTT>inline TTT mrr()
{
	TTT theNumberToRead = 0;
	bool prn = false;
	char c = getchar();
	while (!isdigit(c))
	{
		if (c == '-')prn = true;
		c = getchar();
	}
	while (isdigit(c))
		theNumberToRead = 10 * theNumberToRead + (c ^ 48), c = getchar();
	return prn ? -theNumberToRead : theNumberToRead;
}
template<typename T>void my_write(T x)
{
	if (x)
		my_write(x / 10),
		putchar(x % 10 ^ 48);
}
template<typename T>void mw(T x, char mid)
{
	if (x)
	{
		if (x < 0)
			putchar('-'),
			x = -x;
		my_write(x);
	}
	else putchar(48);
	if (mid)
		putchar(mid);
}
// ******************************************华丽的分割线******************************************
// ******************************************华丽的分割线******************************************
// ******************************************华丽的分割线******************************************
// ******************************************华丽的分割线******************************************
// ******************************************华丽的分割线******************************************
int dp[40000];
void solve()
{
	int n;
	mr(n);
	fill(dp, dp + n, INT_MAX);
	for (int i = 1, x; i <= n; ++i)
	{
		mr(x);
		*lower_bound(dp + 1, dp + i, x) = x;
	}
	mw(lower_bound(dp + 1, dp + n, INT_MAX) - dp - 1, '\n');
}
int main()
{
	int t;
	mr(t);
	while (t--)
		solve();
	return 0;
}

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