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Re:请不要想复杂了,对付最近点对最好的办法永远是旋转坐标系+O(n^2)暴力In Reply To:请不要想复杂了,对付最近点对最好的办法永远是旋转坐标系+O(n^2)暴力 Posted by:KomejiSylfii at 2014-06-06 11:03:48 > 附赠代码
> #include <cmath>
> #include <cstdio>
> #include <cstring>
> #include <algorithm>
> using namespace std;
>
> int T;
>
> const double ran = 115.15215;
>
> struct vec { double x, y; } ;
>
> vec operator - (vec a, vec b) { return (vec) { a.x - b.x, a.y - b.y } ; }
>
> double dis(vec a) { return sqrt(a.x * a.x + a.y * a.y); }
>
> vec rota(vec a, double b)
> { return (vec) { cos(b) * a.x - sin(b) * a.y, sin(b) * a.x + cos(b) * a.y }; }
>
> bool cmp(const vec &a, const vec &b)
> { return a.x == b.x ? a.y < b.y : a.x < b.x; }
>
> vec a[100010];
> vec b[100010];
>
> int n;
>
> int main()
> {
> freopen("3714.in", "r", stdin);
> freopen("3714.out", "w", stdout);
>
> scanf("%d", &T);
> while (T--)
> {
> double ans = 1e11;
> scanf("%d", &n);
> for (int i = 1; i <= n; ++i)
> {
> scanf("%lf%lf", &a[i].x, &a[i].y);
> rota(a[i], ran);
> }
> for (int i = 1; i <= n; ++i)
> {
> scanf("%lf%lf", &b[i].x, &b[i].y);
> rota(b[i], ran);
> }
>
> sort(a + 1, a + n + 1, cmp);
> sort(b + 1, b + n + 1, cmp);
>
> int t = 1;
> for (int i = 1; i <= n; ++i)
> {
> while (t < n && cmp(a[t + 1], b[i])) ++t;
> for (int j = t; j <= n; ++j)
> {
> if (fabs(a[j].x - b[i].x) > ans) break;
> ans = min(ans, dis(a[j] - b[i]));
> }
> for (int j = t - 1; j; --j)
> {
> if (fabs(a[j].x - b[i].x) > ans) break;
> ans = min(ans, dis(a[j] - b[i]));
> }
> }
> printf("%.3f\n", ans);
> }
> return 0;
> }
>
>
>
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