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Re:提供一种思路:可以吧1点的值设为无穷,然后其他点赋值为0,应该很多算法都可以跑In Reply To:提供一种思路:可以吧1点的值设为无穷,然后其他点赋值为0,应该很多算法都可以跑 Posted by:swust5120171204 at 2019-06-06 19:59:35 > 我跑的是spfa
> #include<stdio.h>
> #include<string.h>
> #include<iostream>
> #include<algorithm>
> #include<math.h>
> #include<set>
> #include<stack>
> #include<vector>
> #include<map>
> #include<queue>
> #define myself i,l,r
> #define lson i<<1
> #define rson i<<1|1
> #define Lson i<<1,l,mid
> #define Rson i<<1|1,mid+1,r
> #define half (l+r)/2
> #define inff 0x3f3f3f3f
> #define lowbit(x) x&(-x)
> #define PI 3.14159265358979323846
> #define min4(a,b,c,d) min(min(a,b),min(c,d))
> #define min3(x,y,z) min(min(x,y),min(y,z))
> #define pii make_pair
> #define pr pair<int,int>
> const int dir[4][2]={0,1,0,-1,1,0,-1,0};
> typedef long long ll;
> const ll inFF=9223372036854775807;
> typedef unsigned long long ull;
> using namespace std;
> const int maxn=1e5+5;
> int head[maxn],sign;
> int d[maxn],vis[maxn];
> int n,m;
> struct node
> {
> int to,p,val;
> }edge[maxn];
> void add(int u,int v,int val)
> {
> edge[sign]=node{v,head[u],val};
> head[u]=sign++;
> }
> void init()
> {
> sign=0;
> memset(head,-1,sizeof(head));
> }
> int spfa()
> {
> for(int i=0;i<=n;i++)
> {
> d[i]=0;
> vis[i]=0;
> }
> d[1]=inff;
> queue<int> q;
> q.push(1);
> while(!q.empty())
> {
> int u=q.front();
> q.pop(),vis[u]=0;
> for(int i=head[u];~i;i=edge[i].p)
> {
> int v=edge[i].to;
> if(d[v]<min(edge[i].val,d[u]))
> {
> d[v]=min(edge[i].val,d[u]);
> if(!vis[v])
> {
> q.push(v);
> vis[v]=1;
> }
> }
> }
> }
> return d[n];
> }
> int main()
> {
> int t,x,y,z,p=0;
> cin>>t;
> while(t--)
> {
> scanf("%d %d",&n,&m);
> init();
> for(int i=1;i<=m;i++)
> {
> scanf("%d %d %d",&x,&y,&z);
> add(x,y,z),add(y,x,z);
> }
> printf("Scenario #%d:\n",++p);
> cout<<spfa()<<endl;
> printf("\n");
> }
> return 0;
> }
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