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大家都在说离散化的问题,只要不离散化不就好了?RT动态开点线段树他不香吗?
AC代码:
#include<cstdio>
#include<queue>
#include<iostream>
#include<cstring>
#include<algorithm>
using namespace std;
int T,n,cnt,rt,vis[10001],ans;
struct tree
{
int l,r,tag;
}t[10000001];
void change(int l,int r,int &rt,int L,int R,int k)
{
if(!rt)rt=++cnt,t[cnt].l=t[cnt].r=t[cnt].tag=0;
if(L<=l&&r<=R)
{
t[rt].tag=k;
return;
}
if(t[rt].tag)
{
if(!t[rt].l)t[rt].l=++cnt,t[cnt].l=t[cnt].r=t[cnt].tag=0;
t[t[rt].l].tag=t[rt].tag;
if(!t[rt].r)t[rt].r=++cnt,t[cnt].l=t[cnt].r=t[cnt].tag=0;
t[t[rt].r].tag=t[rt].tag;
t[rt].tag=0;
}
int mid=(l+r)>>1;
if(L<=mid)change(l,mid,t[rt].l,L,R,k);
if(R>mid)change(mid+1,r,t[rt].r,L,R,k);
}
void ask(int l,int r,int rt)
{
if(!rt)return;
if(t[rt].tag)
{
if(!vis[t[rt].tag])
vis[t[rt].tag]=1,ans++;
return;
}
int mid=(l+r)>>1;
ask(l,mid,t[rt].l);
ask(mid+1,r,t[rt].r);
}
int main()
{
scanf("%d",&T);
while(T--)
{
cnt=rt=ans=0;
memset(vis,0,sizeof(vis));
scanf("%d",&n);
for(int i=1;i<=n;i++)
{
int l,r;
scanf("%d%d",&l,&r);
change(1,10000000,rt,l,r,i);
}
ask(1,10000000,rt);
printf("%d\n",ans);
}
return 0;
}
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