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Re:做了好几个版本。还是timeout了。。。算了。走人。换一题。。。。In Reply To:做了好几个版本。还是timeout了。。。算了。走人。换一题。。。。 Posted by:274856653 at 2020-12-07 15:35:23 #include <cstdio> #include <iostream> #include <cstring> #include <vector> #include <bitset> #include <stdio.h> #include <stdlib.h> #include <string.h> #include <math.h> #define MAX_N 18 #define MAX_V (1<<MAX_N) using namespace std; int T, n, k; char C[MAX_V]; void init() { memset((char *)&C, 0, sizeof(C)); } void printbit(bool bit[], int len) { printf("printbit len = %d\n", len); for(int i = 0; i<len; i++) printf("%d", bit[i]); printf("\n"); } int dfs(int nn, int kk, bool *bit, int tot) { int sum = 0, temp = 0; int half = tot/2 ; //cout<<"dfs nn = "<<nn<<",kk = "<<kk<<", tot = "<<tot<<", half = "<<half<<endl; //printbit(bit, tot); if(nn<kk) { return 0; } if(nn == 0 && kk == 0) { if(bit[0]) return 1; else return 0; } //xn == 0; bool* bit0 = new bool[half]; memset(bit0, 0, half); memcpy(bit0, bit, half); //printf("bit0 "); //printbit(bit0, half); temp = dfs(nn-1, kk, bit0, half ); sum += temp; delete [] bit0; //xn == 1; if(kk>0) { bool* bit1 = new bool[half]; memset(bit1, 0, half); for(int i = 0; i<half; i++) { bit1[i] = bit[i]^bit[i+half]; } // printf("bit1 "); // printbit(bit1, half); temp = dfs(nn-1, kk-1, bit1, half); sum += temp; delete [] bit1; } return sum; } int main() { int i; int len, ans; scanf("%d", &T); // printf("T = %d, MAX_V = %d\n", T, MAX_V); while(T--) { init(); scanf("%d %d %s", &n, &k, C); len = strlen(C); // printf("n = %d, k = %d, C= %s, len = %d\n", n, k, C, len); bool* coe = new bool[len]; memset(coe, 0, len); for(i = 0; i<len; i++) { if(C[i] == '1') { coe[i] = true; }else { coe[i] = false; } } //printbit(coe, len); ans = dfs(n, k, coe, len ); printf("%d\n", ans); delete[] coe; } } 几经波折。做了5,6个版本总算不timeout了。。。。还有我用c++提交wa。g++ok了。不过本机上也是用g++提交的。。。 Followed by:
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