#include<iostream>
using namespace std;
int main() {
	int s, d;
	while (cin >> s >> d) {
		int i, t;
		for (i = 5; i && i * s - (5 - i) * d >= 0; i--);
		if (i > 1 && (t = 2 * s + 2 * (i * s - (5 - i) * d)) > 0)cout << t << endl;
		else if (i == 1 && (t = s - d + 2 * (i * s - (5 - i) * d)) > 0)cout << t << endl;
		else cout << "Deficit\n";
	}
	return 0;
}

• Re:贴个ac代码，这题真签到 (7) zpb 2020-11-19 04:52:22