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注意点:1.过滤Q和Z,2.注意输出格式

Posted by zlf1215 at 2020-08-18 15:39:28 on Problem 1002
1.“Q”和“Z”要和“-”一起过滤掉,不然会WA
2.注意输出格式,printf("%03d-%04d %d",)
另附自己垃圾代码
#include<cstdio>
#include<cstring>
#include<map>
#include<queue>
#include<algorithm>
using namespace std;

int main()
{
	int N,n;
	scanf("%d",&N);
	n=N;
	char str[100];
	map<int, int> m;	
	priority_queue<int,vector<int>, greater<int> > q;
	for(int i=0;i<n;i++)
	{
		scanf("%s",str);
		int bz=0,t;
		for(int j=0;j<strlen(str);j++)
		{
			if(str[j]=='-'||str[j]=='Q'||str[j]=='Z')
				continue;
			else 
			{
				if(str[j]>='0'&&str[j]<='9')
				{
					t=str[j]-'0';
				}
				else
					switch(str[j])
					{
						case 'A':
						case 'B':
						case 'C': t=2;break;
						case 'D':
						case 'E':
						case 'F': t=3;break;
						case 'G':
						case 'H':
						case 'I': t=4;break;
						case 'J': 
						case 'K':
						case 'L': t=5;break;
						case 'M':
						case 'N':
						case 'O': t=6;break;
						case 'P':
						case 'R':
						case 'S': t=7;break;
						case 'T':
						case 'U':
						case 'V': t=8;break;
						case 'W':
						case 'X':
						case 'Y': t=9;break;
						default: break;		
					}
			}
			
			bz=bz*10+t;					
		}
		if(m[bz]++==0)	q.push(bz);	
	}

	int flag=1;
	while(!q.empty())
	{
		if(m[q.top()]!=1)
		{
			printf("%03d-%04d %d\n",q.top()/10000,q.top()%10000,m[q.top()]);
			flag=0;
		}	
		q.pop();
	}
	if(flag)	puts("No duplicates.\n");
	
	return 0;
}

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