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Re:二分: l=0,r=1000 精度<0.0001 四舍五入: cout << (int)(100 * ans+0.5) << endl;In Reply To:二分: l=0,r=1000 精度<0.0001 四舍五入: cout << (int)(100 * ans+0.5) << endl; Posted by:marszed at 2017-07-14 19:32:43 > rt 几个坑点 > 当然可以更优啦 不过这样就可以AC了 感谢！ Followed by: Post your reply here: |
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