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以 与 1到m的与m互素的数的个数为一个周期 记录互素的数为j 则k/j*m + a[k%j-1] 即为答案k%j!=0 则k/j*m +a[k%j-1] k%j==0 则(k/j-1)*m +a[j-1] Followed by: Post your reply here: |
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