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可能有重复数字,可以这样“打表”#include <cstdio>
#include <cstring>
using namespace std;
int n,cnt=0,a[20]={1},c[105][20],vis[105],ans;
void dfs(int t,int now)
{
if(now>n||t>=ans) return;
if(now==n)
{
if(t<ans)
{
ans=t;
c[n][0]=t;
for (int i=1;i<=t;i++) c[n][i]=a[i-1];
}
return;
}
memset(vis,0,sizeof(vis));
for (int i=t-1;i>=0;i--)
for (int j=i;j>=0;j--)
{
a[t]=a[i]+a[j];
if(a[t]<a[t-1])break;
if(vis[a[t]]==0)
{
vis[a[t]]=1;
dfs(t+1,a[t]);
}
}
}
int main()
{
while(++n<=100)
{
ans=0x3f3f3f3f;
dfs(1,1);
}
while(scanf("%d",&n)&&n)
{
for (int i=1;i<c[n][0];i++) printf("%d ",c[n][i]);
printf("%d\n",c[n][c[n][0]]);
}
return 0;
}
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