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Re:求救,nlogn半平面交模板过不了In Reply To:求救,nlogn半平面交模板过不了 Posted by:Yang_Ming at 2017-01-20 23:30:54 > #include<algorithm>
> #include<iostream>
> #include<iomanip>
> #include<cstring>
> #include<cstdlib>
> #include<vector>
> #include<cstdio>
> #include<cmath>
> #include<queue>
> using namespace std;
> inline const int Get_Int() {
> int num=0,bj=1;
> char x=getchar();
> while(x<'0'||x>'9') {
> if(x=='-')bj=-1;
> x=getchar();
> }
> while(x>='0'&&x<='9') {
> num=num*10+x-'0';
> x=getchar();
> }
> return num*bj;
> }
> const double eps=1e-8;
> int DoubleCompare(double x) { //精度三出口判断与0关系
> if(fabs(x)<eps)return 0; //=0
> else if(x<0)return -1; //<0
> else return 1; //>0
> }
> struct Point {
> double x,y;
> Point(double _x,double _y):x(_x),y(_y){}
> Point(){}
> Point operator + (const Point& a) const {
> return Point(x+a.x,y+a.y);
> }
> Point operator - (const Point& a) const {
> return Point(a.x-x,a.y-y);
> }
> Point operator * (const double a) const {
> return Point(x*a,y*a);
> }
> } ;
> typedef Point Vector;
> double Cross(Vector a,Vector b) { //叉积
> return a.x*b.y-b.x*a.y;
> }
> double Area(Point a,Point b,Point c) { //三点的平行四边形有向面积
> Vector u=b-a,v=c-a;
> return Cross(u,v);
> }
> double Area(int n,Point* P) { //计算多边形有向面积(剖分法)
> double ans=0;
> for(int i=2; i<n; i++)ans+=Area(P[1],P[i],P[i+1]);
> return ans/2;
> }
> struct Line { //有向直线,左边为半平面
> Point p; //直线上任意一点
> Vector v; //方向向量
> double ang;
> Line() {}
> Line(Point p,Vector v):p(p),v(v) {
> ang=atan2(v.y,v.x);
> }
> bool operator < (const Line& L) const {
> return ang<L.ang;
> }
> };
> bool OnLeft(Line L,Point p) { //判断点p是否在有向直线L左边(若不舍直线上的点则加上等号)
> return DoubleCompare(Cross(L.v,L.p-p))>=0;
> }
> Point GetIntersection(Line a,Line b) {
> Vector u=a.p-b.p;
> double t=Cross(u,b.v)/Cross(a.v,b.v);
> return a.p+a.v*t;
> }
> int HalfplaneIntersection(int n,Line* L,Point* poly) {
> sort(L+1,L+n+1); //极角排序
> int first=1,last=1;
> Point p[n+5];
> Line q[n+5];
> q[last]=L[1];
> for(int i=2; i<=n; i++) {
> while(first<last&&!OnLeft(L[i],p[last-1]))last--;
> while(first<last&&!OnLeft(L[i],p[first]))first++;
> q[++last]=L[i];
> if(fabs(Cross(q[last].v,q[last-1].v))<eps) { //平行同向,取内侧
> last--;
> if(!OnLeft(L[i],p[last-1]))q[last]=L[i];
> }
> if(first<last)p[last-1]=GetIntersection(q[last-1],q[last]);
> }
> while(first<last&&!OnLeft(q[first],p[last-1]))last--; //删除无用平面
> if(last-first<=1)return 0; //空集
> p[last]=GetIntersection(q[last],q[first]);
> int m=0;
> for(int i=first; i<=last; i++)poly[++m]=p[i];
> return m;
> }
> ///////////////
> Point a[10005],p[10005];
> Line l[10005];
> int n,m,sum=0,k;
> int main() {
> k=Get_Int();
> while(k--) {
> scanf("%d",&n);
> sum=0;
> for(int i=1; i<=n; i++)scanf("%lf%lf",&p[i].x,&p[i].y);
> l[++sum]=Line(p[1],p[1]-p[n]);
> for(int i=2; i<=n; i++)l[++sum]=Line(p[i],p[i]-p[i-1]);
> int cnt=HalfplaneIntersection(sum,l,p);
> printf("%0.2lf\n",fabs(Area(cnt,p)));
> }
> return 0;
> }
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