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Re:这题不科学啊,同样的数据,两个ac掉的代码跑出来的不一样啊In Reply To:这题不科学啊,同样的数据,两个ac掉的代码跑出来的不一样啊 Posted by:201293123 at 2013-04-10 23:38:33 > 5 6
> 1 2 100
> 2 3 100
> 3 4 100
> 4 5 100
> 3 5 200
> 2 5 700
>
> #include <stdio.h>
> #define QR 65536
> #define MAX 0x7FFFFFFF
> /* POJ 3255: Roadblocks */
> typedef struct str_vec
> {
> int to;
> int length;
> struct str_vec *next;
> } vector;
> vector chain[5100];
> int side_a[100100], side_b[100100], side_l[100100];
> int dist_0[5100];
> int dist_n[5100];
> int queue[QR], add, now, n;
> void spfa (int source, int *dist)
> {
> vector *p;
> int cur, tar, l, i;
>
> add = now = 0;
> queue[add++] = source;
> for (i = 0; i < n; i++)
> dist[i] = MAX;
> dist[source] = 0;
> while (now != add)
> {
> cur = queue[(now++) % QR];
> p = (chain + cur)->next;
> while (p != NULL)
> {
> tar = p->to;
> l = p->length;
> if (dist[cur] + l < dist[tar])
> {
> dist[tar] = dist[cur] + l;
> queue[(add++) % QR] = tar;
> }
> p = p->next;
> }
> }
> return;
> }
> int main ()
> {
> int m, i, st, ed, len, ans = MAX, sp, sn;
> vector *p, *r;
>
> scanf("%d %d", &n, &m);
>
> for (i = 0; i < n; i++)
> chain[i].to = i, chain[i].next = NULL;
>
> for (i = 0; i < m; i++)
> {
> scanf("%d %d %d", &st, &ed, &len);
> st--, ed--;
> side_a[i] = st, side_b[i] = ed, side_l[i] = len;
>
> r = chain + st;
> while (r->next != NULL) r = r->next;
> p = (vector *)malloc(sizeof(vector));
> p->to = ed, p->length = len, p->next = NULL;
> r->next = p;
>
> r = chain + ed;
> while (r->next != NULL) r = r->next;
> p = (vector *)malloc(sizeof(vector));
> p->to = st, p->length = len, p->next = NULL;
> r->next = p;
> }
>
> spfa(0, dist_0);
> spfa(n - 1, dist_n);
> sp = dist_0[n - 1];
>
> for (i = 0; i < m; i++)
> {
> st = side_a[i], ed = side_b[i], len = side_l[i];
> sn = dist_0[st] + len + dist_n[ed];
> if (sn != sp && sn < ans) ans = sn;
> sn = dist_0[ed] + len + dist_n[st];
> if (sn != sp && sn < ans) ans = sn;
> }
>
> printf("%d\n", ans);
> //system("pause");
>
> return 0;
> }
> 这跑出来是600
>
>
>
> #include<iostream>
> #include<queue>
> #define MAXN 200001
> #include<string.h>
> #include<stdio.h>
> using namespace std;
> struct node
> {
> int h,g,p;
> bool operator < (node a) const
> {
> return a.h+a.g<h+g;
> }
> };
> struct nodeOfLine
> {
> int x,y,w,next;
> }line[MAXN];
> int n,r,link[5001],g[5001];
> priority_queue<node> myqueue;
> void djikstra()
> {
> int i,j,k,t;
> bool used[MAXN];
> memset(g,0x7F,sizeof(g));
> memset(used,false,sizeof(used));
> g[n]=0;
> for (t=1;t<=n;t++)
> {
> j=0;
> for (i=1;i<=n;i++)
> if (!used[i] && (!j || g[i]<g[j])) j=i;
> used[j]=true;
> k=link[j];
> while (k)
> {
> if (g[line[k].y]>g[line[k].x]+line[k].w)
> g[line[k].y]=g[line[k].x]+line[k].w;
> k=line[k].next;
> }
> }
> return;
> }
> int Astar()
> {
> node h,temp;
> int times[5001],k;
> while (!myqueue.empty()) myqueue.pop();
> memset(times,0,sizeof(times));
> h.p=1; h.h=h.g=0;
> myqueue.push(h);
> while (!myqueue.empty())
> {
> h=myqueue.top();
> myqueue.pop();
> times[h.p]++;
> if (times[h.p]>2) continue;
> if (times[h.p]==2 && h.p==n) return h.h+h.g;
> k=link[h.p];
> while (k)
> {
> temp.p=line[k].y;
> temp.h=h.h+line[k].w;
> temp.g=g[line[k].y];
> myqueue.push(temp);
> k=line[k].next;
> }
> }
> return -1;
> }
> int main()
> {
> scanf("%d%d",&n,&r);
> memset(link,0,sizeof(link));
> for (int i=1;i<=r;i++)
> {
> scanf("%d%d%d",&line[i*2-1].x,&line[i*2-1].y,&line[i*2-1].w);
> line[i*2-1].next=link[line[i*2-1].x]; link[line[i*2-1].x]=i*2-1;
> line[i*2].x=line[i*2-1].y; line[i*2].y=line[i*2-1].x; line[i*2].w=line[i*2-1].w;
> line[i*2].next=link[line[i*2].x]; link[line[i*2].x]=i*2;
> }
> r*=2;
> djikstra();
> printf("%d\n",Astar());
> return 0;
> }
>
>
>
> 这跑出来是400
> 不科学啊
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