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AC (/≧▽≦)/感觉这题并不难呀#include <iostream>
#include <stdio.h>
#include <iomanip>
#include <math.h>
#include <string.h>
#include <algorithm>
#include <vector>
#include <stack>
#include <queue>
#include <map>
#include <set>
#define inf 99999999
typedef long long ll;
typedef unsigned long long ull;
using namespace std;
int tar,l,maxs=0;
map<int,int> mp;
vector<int> vec,tvec;
string num;
void dfs(int ans,int n)//在第n位之前切割
{
if(n==l)
{
if(ans<=tar&&ans>=maxs)
{
mp[ans]++;
tvec=vec;
maxs=max(maxs,ans);
}
return ;
}
for(int i=n+1;i<=l;i++)//选择下一个切割位置:i
{
int res=0;
for(int j=i-1,k=0;j>=n;j--,k++) res+=pow(10,k)*(num[j]-'0');
vec.push_back(res);
dfs(ans+res,i);
vec.pop_back();
}
}
int main()
{
while(cin>>tar>>num)
{
if(tar==0&&num=="0")return 0;
mp.clear();
vec.clear();
maxs=0;
l=num.length();
dfs(0,0);
if(maxs==0)cout<<"error";
else if(mp[maxs]>1)cout<<"rejected";
else
{
cout<<maxs;
for(int i=0;i<tvec.size();i++) cout<<" "<<tvec[i];
}
cout<<endl;
}
}
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