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利用数学In Reply To:怎么加速啊,有什么更快的算法吗? Posted by:dexter at 2004-03-07 21:17:36 我记得没错的话,是求n!的最后一位非零的吧?记为f(n) 根据式子 n-1 (5n)! = (10^n)n! ∏(5i+1)(5i+2)(5i+3)(5i+4)/2 i=0 可证明 f(5n)≡(2^n)f(n) (mod10)就可以了 Followed by:
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