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贴一个树链剖分的代码...

Posted by ibilllee at 2018-07-18 21:28:25 on Problem 1986
由于没修改,所以就不用线段树啦,直接记个前缀和就好啦....
#include<set>
#include<map>
#include<queue>
#include<stack>
#include<cmath>
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
#define RG register int
#define rep(i,a,b)    for(RG i=a;i<=b;++i)
#define per(i,a,b)    for(RG i=a;i>=b;--i)
#define ll long long
#define inf (1<<29)
#define maxn 100005
#define add(x,y,z) e[++cnt]=(E){y,head[x],z},head[x]=cnt
using namespace std;
int n,m,cnt,id,T;
int head[maxn],val[maxn],sz[maxn],son[maxn],fa[maxn],dep[maxn],top[maxn],dfn[maxn],node[maxn],imos[maxn];
struct E{
	int v,next,val;
}e[maxn<<1];
inline int read()
{
	int x=0,f=1;char c=getchar();
	while(c<'0'||c>'9'){if(c=='-')f=-1;c=getchar();}
	while(c>='0'&&c<='9'){x=x*10+c-'0';c=getchar();}
	return x*f;
}

void dfs1(int u,int pa)
{
	sz[u]=1,fa[u]=pa,dep[u]=dep[pa]+1;
	for(RG i=head[u];i;i=e[i].next)
	{
		int v=e[i].v;
		if(v==pa)	continue;
		val[v]=e[i].val;
		dfs1(v,u);
		sz[u]+=sz[v];
		if(sz[v]>sz[son[u]])	son[u]=v;
	}
}

void dfs2(int u,int tp)
{
	dfn[u]=++id,top[u]=tp,node[id]=u;
	if(!son[u])	return;
	dfs2(son[u],tp);
	for(RG i=head[u];i;i=e[i].next)
	{
		if(e[i].v!=fa[u]&&e[i].v!=son[u])	dfs2(e[i].v,e[i].v);
	}
}

void lca()
{
	int x=read(),y=read(),ans=0;
	while(top[x]!=top[y])
	{
		if(dep[top[x]]<dep[top[y]])	swap(x,y);
		ans+=imos[dfn[x]]-imos[dfn[top[x]]-1];
		x=fa[top[x]];
	}
	if(dep[x]>dep[y]) swap(x,y);
	ans+=imos[dfn[y]]-imos[dfn[x]];
	printf("%d\n",ans);
}

int main()
{
	n=read(),m=read();
	rep(i,1,m)
	{
		RG a=read(),b=read(),c=read();getchar();
		add(a,b,c),add(b,a,c);
	}
	dfs1(1,0);
	dfs2(1,0);
	rep(i,1,n) imos[i]=val[node[i]]+imos[i-1];	
	T=read();
	rep(t,1,T)
		lca();
	return 0;
}

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