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不行,有强迫症,HASH总觉得有bug,不严谨,楼主这种方法,从逻辑上必然成立,不过就是写的太丑,我的比较漂亮In Reply To:判断雪花是否相同,其实也不难,翻转和移动 6次 就能判断出来。 Posted by:tangguojun at 2017-09-27 23:57:41 #include<iostream>
#include<cstdio>
#include<set>
#include<algorithm>
using namespace std;
struct node
{
int a[6];
long long sum;
};
node a[1000010];
bool cmp(node a,node b)
{
if(a.sum<b.sum)
return true;
return false;
}
bool jud(int x,int y)
{
for(int i=0;i<6;++i)
{
int flag=1;
for(int j=0;j<6;++j)
{
if(a[x].a[j]!=a[y].a[(j+i)%6])
{
flag=0;
break;
}
}
if(flag)
return true;
}
for(int i=0;i<6;++i)
{
int flag=1;
for(int j=0;j<6;++j)
{
if(a[x].a[j]!=a[y].a[(6-j+i)%6])
{
flag=0;
break;
}
}
if(flag)
return true;
}
return false;
}
int main()
{
int flag=1,N;
scanf("%d",&N);
for(int i=0;i<N;++i)
{
scanf("%d%d%d%d%d%d",&a[i].a[0],&a[i].a[1],&a[i].a[2],&a[i].a[3],&a[i].a[4],&a[i].a[5]);
a[i].sum=0;
a[i].sum=a[i].a[0]+a[i].a[1]+a[i].a[2]+a[i].a[3]+a[i].a[4]+a[i].a[5];
}
sort(a,a+N,cmp);
int j;
for(int i=0;i<N&&flag;++i)
{
j=i+1;
while(j<N&&a[i].sum==a[j].sum)
{
if(jud(i,j))
{
flag=0;
break;
}
++j;
}
}
if(flag)
printf("No two snowflakes are alike.\n");
else
printf("Twin snowflakes found.\n");
return 0;
}
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