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Re:RTIn Reply To:RT Posted by:2730052770 at 2017-12-04 19:06:31 > #include<cstdio>
> #include<iostream>
> #include<cstring>
> #include<algorithm>
> #define N 20005
> using namespace std;
> int s[N],sa[N],rk[N],ht[N],c[N],a[2][N],mx[20][N],mn[20][N],lg[N];
> void build(int n,int m)
> {
> int i,k,p,*x=a[0],*y=a[1];
> for(i=0;i<m;i++)c[i]=0;
> for(i=0;i<n;i++)c[x[i]=s[i]]++;
> for(i=1;i<m;i++)c[i]+=c[i-1];
> for(i=n-1;i>=0;i--)sa[--c[x[i]]]=i;
> for(k=1;k<=n;k<<=1){
> p=0;
> for(i=n-k;i<n;i++)y[p++]=i;
> for(i=0;i<n;i++)if(sa[i]>=k)y[p++]=sa[i]-k;
> for(i=0;i<m;i++)c[i]=0;
> for(i=0;i<n;i++)c[x[i]]++;
> for(i=1;i<m;i++)c[i]+=c[i-1];
> for(i=n-1;i>=0;i--)sa[--c[x[y[i]]]]=y[i];
> swap(x,y);
> m=1,x[sa[0]]=0,y[n]=-1;
> for(i=1;i<n;i++)
> x[sa[i]]=y[sa[i]]==y[sa[i-1]]&&y[sa[i]+k]==y[sa[i-1]+k]?m-1:m++;
> if(m>=n)break;
> }
> memcpy(rk,x,sizeof(rk));
> k=0,ht[0]=0;
> for(i=0;i<n;i++){
> if(k)k--;
> if(!rk[i])continue;
> int j=sa[rk[i]-1];
> while(s[i+k]==s[j+k]&&i+k<n&&j+k<n)k++;
> ht[rk[i]]=k;
> }
> }
> void ST(int n){
> memcpy(mx[0],sa,sizeof(sa));
> memcpy(mn[0],sa,sizeof(sa));
> for(int i=1;i<20;i++)
> for(int j=0;j+(1<<i)-1<n;j++)
> mx[i][j]=max(mx[i-1][j],mx[i-1][j+(1<<(i-1))]),
> mn[i][j]=min(mn[i-1][j],mn[i-1][j+(1<<(i-1))]);
> for(int i=2;i<N;i++)lg[i]=lg[i>>1]+1;
> }
> bool query(int l,int r,int lmt){
> int Lg=lg[r-l+1],len=1<<Lg;
> return max(mx[Lg][l],mx[Lg][r-len+1])-min(mn[Lg][l],mn[Lg][r-len+1])>=lmt;
> }
> bool check(int mid,int n){
> int pre=0;
> ht[n]=0x80000000;
> for(int i=1;i<=n;i++)if(ht[i]<mid){
> if(query(pre,i-1,mid+1))return 1;//×¢ÒâÊÇmid+1ÒòΪҪÇó²»Öظ´
> pre=i;//Ôò²îÖµÊý×é(¼´sÊý×é)ÖеÄÁ½¶ÎÓ¦¸ÃÊÇÖÁÉÙ¸ôÁËÒ»¸öÊýµÄ
> }//¶ø²»ÄܽôÌù×Å,½ôÌù×ŵϰÔÊý×é¾Í»áÓÐÖØ¸´
> return 0;
> }
> int main()
> {
> int n;
> while(cin>>n&&n)
> {
> for(int i=0;i<n;i++)scanf("%d",&s[i]);
> for(int i=n-1;i>=1;i--)s[i]-=s[i-1];
> n--;
> for(int i=0;i<n;i++)s[i]=s[i+1]+100;
> s[n]=0;
> build(n,200);
> //for(int i=0;i<n;i++)printf("%d %d %d\n",s[i],sa[rk[i]],ht[i]);
> ST(n);
> int l=4,r=n,mid,ans=-1;
> while(l<=r){
> mid=(l+r)>>1;
> if(check(mid,n)) ans=mid,l=mid+1;
> else r=mid-1;
> }
> cout<<ans+1<<endl;
> }
> return 0;
> }
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