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大佬们帮忙看一下为什么编译错误,我在我的编译器上编译没问题#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<math.h>
#define swap(a,b){a=a+b;b=a-b;a=a-b;}
int CheckAndReturnNum(char *s);
int main(void) {
int n,i,j,q,count=0;
scanf("%d", &n);
int *data = (int *)malloc(n*sizeof(int));
char s[30];
for (i = 0; i <n; i++)
{
scanf("%s",s);
data[i]=CheckAndReturnNum(s);
}
//printf("%03d-%04d %d\n", data[i] / 10000, data[i] % 10000);
for (i = 0; i < n; i++) {
for (j = i + 1; j < n; j++)
{
if (data[i] < data[j])
swap(data[i], data[j]);
}
}
for ( i = 0; i < n; i++)
{
count = 1;
while (data[i]==data[i+1])
{
i++;
count++;
}
if (count > 1)
printf("%03d-%04d %d\n", data[i] / 10000, data[i] % 10000, count);
}
free(data);
return 0;
}
int CheckAndReturnNum(char *s) {
int i, sum = 0,m=0;
for (i = strlen(s) - 1; i >= 0; i--)
{
if (s[i] >= '0'&&*(s + i) <= '9' || *(s + i) >= 'A'&&*(s + i) <= 'Z') {
if (s[i] >= '0'&&*(s + i) <= '9')
{
sum += (s[i] - '0') * pow(10, m);
}
if (*(s + i) >= 'A'&&*(s + i) <= 'Z')
{
if (s[i] > 'Q'&&s[i] < 'Z')
sum += ((s[i] - 'Q') / 3 + 2)*pow(10,m);
else
sum += ((s[i] - 'A') / 3 + 2)*pow(10,m);
}
m++;
}
}
return sum;
}
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