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Re:poj3009为什么撞到石头后,把1变成0,然后递归dfs,后又要把0还原成1?In Reply To:poj3009为什么撞到石头后,把1变成0,然后递归dfs,后又要把0还原成1? Posted by:184762651 at 2015-01-10 15:55:16 > poj3009为什么撞到石头后,把1变成0,然后递归dfs,后又要把0还原成1? > 主要dfs代码如下 > for (int i = 0; i < 4; i++){ > > xt = x; > yt = y; > > while ( (0<=xt&&xt<h) && (0<=yt&&yt<w) // 向某个方向一直飞啊飞~ > && (map[xt][yt] == 0 or map[xt][yt] == 2)){//vacant square or start > xt += dh[i]; > yt += dw[i]; > } > > if (0<=xt&&xt<h && 0<=yt&&yt<w && map[xt][yt] == 3){ // 飞过(到)目标了 > if (times+1 < ans){ > ans = times+1; > } > } > else if (!(xt-dh[i]==x && yt-dw[i]==y) // 必须有空地才能飞啊,待在原地不算啊 > && 0<=xt&&xt<h && 0<=yt&&yt<w && map[xt][yt] == 1){ // blocks > map[xt][yt] = 0; > dfs(xt-dh[i], yt-dw[i], times+1); > map[xt][yt] = 1; //此处 > } > } Followed by: Post your reply here: |
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