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Re:我发现我的代码越来越有美感了。。。~~层次分明的代码就是容易1A

Posted by 13242767175 at 2017-09-22 16:23:20 on Problem 2632
In Reply To:我发现我的代码越来越有美感了。。。~~层次分明的代码就是容易1A Posted by:xiangel at 2012-10-16 01:49:46
> #include <cstdio>
> 
> using namespace std;
> 
> const int N = 105;
> 
> struct rob
> {
> 	int x, y, d;
> }rob[N];
> 
> struct move
> {
> 	int id, tap, times;
> }ms[N];
> 
> int on[N][N];
> int t, m, n, nums, moves;
> 
> void input()
> {
> 	scanf("%d %d", &m, &n);
> 	for (int i = 1; i <= n; ++i)
> 		for (int j = 1; j <= m; ++j)
> 			on[i][j] = 0;
> 	char c;
> 	scanf("%d %d", &nums, &moves);
> 	for (int i = 1; i <= nums; ++i)
> 	{
> 		scanf("%d %d %c", &rob[i].y, &rob[i].x, &c);
> 		on[rob[i].x][rob[i].y] = i;
> 		switch(c)
> 		{
> 			case 'S':rob[i].d = 0;break;
> 			case 'E':rob[i].d = 1;break;
> 			case 'N':rob[i].d = 2;break;
> 			case 'W':rob[i].d = 3;break;
> 		}
> 	}
> 	for (int i = 1; i <= moves; ++i)
> 	{
> 		scanf("%d %c %d", &ms[i].id, &c, &ms[i].times);
> 		switch(c)
> 		{
> 			case 'L':ms[i].tap = 1;break;
> 			case 'R':ms[i].tap = 2;break;
> 			case 'F':ms[i].tap = 3;break;
> 		}
> 	}
> }
> 
> void output(int one, int two, int w)
> {
> 	if (w == 1)
> 		printf("Robot %d crashes into the wall\n", one);
> 	else
> 		printf("Robot %d crashes into robot %d\n", one, two);
> }
> 
> bool move(int id, int inx, int iny, int times)
> {
> 	int x = rob[id].x;
> 	int y = rob[id].y;
> 	on[x][y] = 0;
> 	for (int i = 0; i < times; ++i)
> 	{
> 		x += inx;
> 		y += iny;
> 		if (x < 1 || x > n || y < 1 || y > m)
> 		{
> 			output(id, 0, 1);
> 			return false;
> 		}
> 		if (on[x][y] != 0)
> 		{
> 			output(id, on[x][y], 2);
> 			return false;
> 		}
> 	}
> 	on[x][y] = id;
> 	rob[id].x = x;
> 	rob[id].y = y;
> 	return true;
> }
> 
> bool change(int id, int tap, int times)
> {
> 	switch(tap)
> 	{
> 		case 1:rob[id].d = (rob[id].d + times) % 4;break;
> 		case 2:rob[id].d = (rob[id].d + 3 * times) % 4;break;
> 		case 3:
> 			switch(rob[id].d)
> 			{
> 				case 0:
> 					if (!move(id, -1,  0, times))
> 						return false;
> 					break;
> 				case 1:
> 					if (!move(id,  0,  1, times))
> 						return false;
> 					break;
> 				case 2:
> 					if (!move(id,  1,  0, times))
> 						return false;
> 					break;
> 				case 3:
> 					if (!move(id,  0, -1, times))
> 						return false;
> 					break;
> 			}
> 			break;
> 	}
> 	return true;
> }
> 
> void solve()
> {
> 	for (int i = 1; i <= moves; ++i)
> 		if (!change(ms[i].id, ms[i].tap, ms[i].times))
> 			return;
> 	puts("OK");
> }
> 
> int main()
> {
> 	scanf("%d", &t);
> 	while (t--)
> 	{
> 		input();
> 		solve();
> 	}
> 	return 0;
> }

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