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二分: l=0,r=1000 精度<0.0001 四舍五入: cout << (int)(100 * ans+0.5) << endl;

Posted by marszed at 2017-07-14 19:32:43 on Problem 2976
rt 几个坑点 
当然可以更优啦 不过这样就可以AC了

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