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发一波福利

Posted by limuye at 2017-07-08 16:42:20 on Problem 1006 and last updated at 2017-07-08 16:43:29
#include<cstdio>
#include<cstring>
using namespace std;
typedef long long ll;
ll exgcd(ll a,ll b,ll &x,ll &y)
{
	if(a==0)
	{
		x=0;y=1;
		return b;
	}
	else
	{
		ll d,tx,ty;
		d=exgcd(b%a,a,tx,ty);
		x=ty-(b/a)*tx;
		y=tx;
		return d;
	}
}
int main()
{
	int t;
	for(int t=1;t;t++)
	{
		ll n;bool bk=true;
		ll b1,m1,b[4],m[4];
		
		
 	    for(int i=1;i<=3;i++)scanf("%lld",&b[i]);
 	    scanf("%lld",&n);
	
		b1=b[1];
		
		if(b1==-1&&b[2]==-1&&b[3]==-1&&n==-1)break;
		
		m1=23;m[2]=28;m[3]=33;
		b1%=23;b[2]%=28;b[3]%=33;
		
    	
		for(int i=2;i<=3;i++)
		{

			ll A,B,K,d,x,y;
			A=m1;B=m[i];K=b[i]-b1;
			d=exgcd(A,B,x,y);
			x=x*(K/d);
			x=(x%(B/d)+(B/d))%(B/d);
			if(K%d!=0)bk=false;
			b1=m1*x+b1;
			m1=m1*m[i]/d;
		}
		printf("Case %d: the next triple peak occurs in ",t);
		if(bk==false)printf("-1 days.\n");
		else 
		{
			if(b1-n>0)printf("%lld days.\n",b1-n);
			else printf("%lld days.\n",b1-n+21252);
		}
	}

	return 0;
}

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