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Re:求易错数据In Reply To:求易错数据 Posted by:120302508 at 2013-01-20 22:42:50 > #include<stdio.h> > > int main() > { > long long int a[101], r, r2; > int n, m, i, j, s, e; > char x; > while (~scanf("%d %d", &n, &m)) > { > for (i = 0; i <= 2 * n; i++) > a[i] = 0; > s = e = n; > r2 = a[n] = (long long int)1 << n; > for (j = 0; j < n; j++) > { > for (i = s; i <= e; i += 2) > { > getchar(); > x = getchar(); > if (x == '*') > { > a[i - 1] += a[i] / 2; > a[i + 1] += a[i] / 2; > a[i] = 0; > } > } > s--; > e++; > } > for (i = 1; i <= 2 * n; i += 2) > { > a[i - 1] += a[i] / 2; > a[i + 1] += a[i] / 2; > a[i] = 0; > } > r = a[2 * m]; > if (r) > { > while (!(r % 2)) > > { > r /= 2; > r2 /= 2; > } > printf("%lld/%lld\n", r, r2); > } > else > printf("0/1\n"); > } > return 0; > } Followed by: Post your reply here: |
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