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这道题明显的动态规划啊啊啊啊啊#include <iostream> #include <algorithm> #include <cstdio> using namespace std; int N,K; const int MAX = 100005; int dp[MAX]; int main(){ cin>>N>>K; for(int i = 0;i <= K;i++){ dp[i] = abs((int)(N - i)); } for(int i = N+1;i <= K;i++){ if(i & 1) // 奇数 { dp[i] = min(dp[i],dp[(i-1)/2]+2); dp[i] = min(dp[i],dp[i-1]+1); dp[i] = min(dp[i],dp[(i+1)/2]+2); } else{ dp[i] = min(dp[i],dp[i/2]+1); dp[i] = min(dp[i],dp[i-1]+1); dp[i] = min(dp[i],dp[i/2 + 1]+2); } } cout<<dp[K]<<endl; return 0; } Followed by:
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