| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
我 m*m*n的复杂度怎么可能超时?????//#include<bits/stdc++.h>
#include <iostream>
#include <string>
#include <queue>
#include <map>
#include <cstring>
#include <cstdio>
#include <cmath>
#include <vector>
using namespace std;
typedef long long LL;
const int MAXN = 10008;
map<string, int> hashG;
int g[MAXN][12];
int n, m, numG;
void read(int nowC)
{
char s[88], str[88];
gets(s);
int ls = strlen(s), k = 0, t = 0;
s[ls++] = ',';
for(int i = 0; i < ls; i++)
{
if (s[i] == ',')
{
str[t] = '\0';
string sp(str);
int tmp = hashG.count(sp);
if (!tmp)
{
hashG[sp] = numG++;
}
g[nowC][k] = hashG[sp];
k++;
t = 0;
continue;
}
str[t++] = s[i];
}
}
int main()
{
scanf("%d%d", &n, &m);
numG = 0;
getchar();
//hashG.clear();
for(int i = 0; i < n; i++)
{
read(i);
}
for(int i = 0; i < m; i++)
for(int j = i+1; j < m; j++)
{
map<pair<int , int>, int> mp;
for(int k = 0; k < n; k++)
{
pair<int, int> nowP = make_pair(g[k][i], g[k][j]);
if (mp.count(nowP))
{
printf("NO\n%d %d\n%d %d\n", mp[nowP]+1, k+1, i+1, j+1);
return 0;
}
mp[nowP] = k;
}
}
printf("YES\n");
return 0;
}
Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator