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简短ac代码//实质求严格上升子序列的长度,动态规划 #include<stdio.h> #include<algorithm> int a[1000], dp[1000]; int main(void) { int n,ans=1; scanf("%d", &n); for (int i = 0; i < n; i++) { scanf("%d", &a[i]); dp[i] = 1; for (int j = 0; j < i; j++) { if (a[j] < a[i]) dp[i] =std:: max(dp[i], dp[j]+1); } ans = std::max(ans, dp[i]); } printf("%d\n", ans); return 0; } Followed by: Post your reply here: |
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