Online Judge | Problem Set | Authors | Online Contests | User | ||||||
---|---|---|---|---|---|---|---|---|---|---|
Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest |
Re:这道题,偶用解析几何过的,求两条直线垂直平分线的交点,即为圆心,然后求半径.看了大家的帖子,学习!!!!!!In Reply To:这道题,偶用解析几何过的,求两条直线垂直平分线的交点,即为圆心,然后求半径.看了大家的帖子,学习!!!!!! Posted by:Ontheline at 2009-02-18 12:18:43 #include <cstdio> #include <cmath> int main() { double x1, y1, x2, y2, x3, y3, X1, Y1, X2, Y2, x, y, k1, k2, r, t; while(~scanf("%lf%lf%lf%lf%lf%lf", &x1, &y1, &x2, &y2, &x3, &y3)){ if(y1 == y2) t = x1, x1 = x3, x3 = t, t = y1, y1 = y3, y3 = t; else if(y1 == y3) t = x1, x1 = x2, x2 = t, t = y1, y1 = y2, y2 = t; X1 = (x1 + x2) / 2, Y1 = (y1 + y2) / 2, k1 = (x1 - x2) / (y2 - y1); X2 = (x1 + x3) / 2, Y2 = (y1 + y3) / 2, k2 = (x1 - x3) / (y3 - y1); x = (Y2 - Y1 + k1 * X1 - k2 * X2) / (k1 - k2); y = k1 * (x - X1) + Y1; r = sqrt((x - x1) * (x - x1) + (y - y1) * (y - y1)); printf("%.2f\n", 2 * 3.141592653589793 * r); } return 0; } //我也是这样做的,有点复杂 Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator