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## Re:楼主，你的数据我都过了，然而还是不行啊，代码附上，求助

Posted by 201600800535 at 2017-04-16 20:54:12 on Problem 1328
In Reply To:楼主，你的数据我都过了，然而还是不行啊，代码附上，求助 Posted by:zcmartin at 2015-12-16 17:02:28
> #include <iostream>
> #include <math.h>
> #include <algorithm>
> #include <stdio.h>
> #include <string.h>
> using namespace std;
> struct sa
> {
>     double x,y,left,right;
> }data[1005];
> double cmp(const sa&a,const sa&b)
> {
>     return a.left>b.left;
> }
> int main()
> {
>     sa tmp;
>     int n;
>     double d;
>     int k=1;
>     while(cin>>n>>d)
>     {
>         memset(data,0,sizeof(data));
>         int sum=1;
>         double maxn=0.0,minn=0.0;
>         if(n==0||d==0)
>             break;
>         for(int i=0;i<n;i++)
>            {
>               cin>>data[i].x>>data[i].y;
>               data[i].left=data[i].x-sqrt(d*d-data[i].y*data[i].y);
>                data[i].right=data[i].x+sqrt(d*d-data[i].y*data[i].y);
>                maxn=max(maxn,data[i].y);
>                minn=min(minn,data[i].y);
>               // cout<<maxn<<endl;
>            }
>          //  cout<<maxn<<endl;
>         sort(data,data+n,cmp);
>         tmp=data[0];
>         if(maxn>d||d<=0||minn<0)
>         {
>
>             printf("Case ");
>             printf("%d",k);
>             printf(": ");
>              cout<<-1<<endl;
>             k++;
>             //break;
>             continue;
>         }
>         else
>             {
>                 for(int i=0;i<n;i++)
>                     if(sqrt((tmp.left-data[i].x)*(tmp.left-data[i].x)+data[i].y*data[i].y)>d)
>                     {
>                         sum++;
>                         tmp=data[i];
>                     }
>             }
>             printf("Case ");
>             printf("%d",k);
>             printf(": ");
>             cout<<sum<<endl;
>             k++;
>            // for(int i=0;i<n;i++)
>              //   cout<<data[i].left<<endl;
>     }
>     return 0;
> }

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