Online Judge | Problem Set | Authors | Online Contests | User | ||||||
---|---|---|---|---|---|---|---|---|---|---|
Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest |
1A,好开心判断是否满流以及添加的边是否为整数 #include <cstdio> #include <algorithm> #include <cstring> #include <iostream> using namespace std; const int oo=1e9; /**oo 表示无穷大*/ const int mm=111111; /**mm 表示边的最大数量,记住要是原图的两倍,在加边的时候都是双向的*/ const int mn=999; /**mn 表示点的最大数量*/ int node,src,dest,edge; /**node 表示节点数,src 表示源点,dest 表示汇点,edge 统计边数*/ int ver[mm],flow[mm],next[mm]; /**ver 边指向的节点,flow 边的容量,next 链表的下一条边*/ int head[mn],work[mn],dis[mn],q[mn]; /**head 节点的链表头,work 用于算法中的临时链表头,dis 计算距离*/ /**初始化链表及图的信息*/ void prepare(int _node,int _src,int _dest) { node=_node,src=_src,dest=_dest; for(int i=0; i<node; ++i)head[i]=-1; edge=0; } /**增加一条u 到v 容量为c 的边*/ void addedge(int u,int v,int c) { ver[edge]=v,flow[edge]=c,next[edge]=head[u],head[u]=edge++; ver[edge]=u,flow[edge]=0,next[edge]=head[v],head[v]=edge++; } /**广搜计算出每个点与源点的最短距离,如果不能到达汇点说明算法结束*/ bool Dinic_bfs() { int i,u,v,l,r=0; for(i=0; i<node; ++i)dis[i]=-1; dis[q[r++]=src]=0; for(l=0; l<r; ++l) for(i=head[u=q[l]]; i>=0; i=next[i]) if(flow[i]&&dis[v=ver[i]]<0) { /**这条边必须有剩余容量*/ dis[q[r++]=v]=dis[u]+1; if(v==dest)return 1; } return 0; } /**寻找可行流的增广路算法,按节点的距离来找,加快速度*/ int Dinic_dfs(int u,int exp) { if(u==dest)return exp; /**work 是临时链表头,这里用i 引用它,这样寻找过的边不再寻找*/ for(int &i=work[u],v,tmp; i>=0; i=next[i]) if(flow[i]&&dis[v=ver[i]]==dis[u]+1&&(tmp=Dinic_dfs(v,min(exp,flow[i])))>0) { flow[i]-=tmp; flow[i^1]+=tmp; /**正反向边容量改变*/ return tmp; } return 0; } int Dinic_flow() { int i,ret=0,delta; while(Dinic_bfs()) { for(i=0; i<node; ++i)work[i]=head[i]; while(delta=Dinic_dfs(src,oo))ret+=delta; } return ret; } int G[mn][mn]; int indeg[mn],outdeg[mn]; int main() { int T,m,s; scanf("%d",&T); while(T--) { memset(indeg,0,sizeof(indeg)); memset(outdeg,0,sizeof(outdeg)); memset(G,0,sizeof(G)); scanf("%d%d",&m,&s); prepare(m+2,0,m+1); for(int i = 0;i < s;i++) { int u,v,state; scanf("%d%d%d",&u,&v,&state); if(u == v) continue; if(state == 0) G[u][v] ++; indeg[v]++; outdeg[u]++; } for(int i = 1;i <= m;i++) { for(int j = 1;j <= m;j++) { if(G[i][j]) addedge(i,j,G[i][j]); } } int exp = 0; for(int i = 1;i <= m;i++) { if(indeg[i] == outdeg[i]) continue; else if(indeg[i] > outdeg[i]) { addedge(i,m+1,(indeg[i]-outdeg[i])/2 ); exp += (indeg[i]-outdeg[i])/2; if((indeg[i]-outdeg[i])/2==0) { goto s; } } else { addedge(0,i,(outdeg[i] - indeg[i])/2); if((indeg[i]-outdeg[i])/2 ==0 ) { goto s; } } } if(exp == Dinic_flow()) { puts("possible"); } else { s:puts("impossible"); } } } Followed by: Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator