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Re:额,试了好几个编译器都能过的代码.In Reply To:额,试了好几个编译器都能过的代码. Posted by:shengrang at 2014-12-27 14:14:00 > 这个题是知道2个根据公式求第三个,,刚开始做以为是告诉你T和D求H..
> 送了无数的WA
>
> 下面代码
>
> #include <stdio.h>
> #include <math.h>
> int main()
> {
> float t,d,h;
> char c1, c2;
> float x, y;
> while(scanf ( " %c", &c1 ) , c1 != 'E')
> {
> scanf ( "%f %c%f", &x, &c2, &y );
> t = d = h = 0;
> if(c1=='T')
> t = x;
> else if(c1=='D')
> d = x;
> else if(c1=='H')
> h = x;
> if(c2=='T')
> t = y;
> else if(c2=='D')
> d = y;
> else if(c2=='H')
> h = y;
> if(t==0)
> {
> t = h - 0.5555*(6.11*exp(5417.7530*(1/273.16-(1/(d+273.16))))-10.0);
> }
> if(d==0)
> {
> d = (h-t)/0.5555+10.0;
> d = d/6.11;
> d = log(d);
> d = d/5417.7530;
> d = 1/273.16 - d;
> d = 1/d-273.16;
> }
> if(h==0)
> {
> h = t + 0.5555*(6.11*exp(5417.7530*(1/273.16-(1/(d+273.16))))-10.0);
> }
> printf ( "T %.1f D %.1f H %.1f\n", t, d, h );
> }
> return 0;
> }
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