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AH/AC = S△DEF/(2 * S△ABC)利用等面积以及三角形相似关系，最终可以得到 AH S△DEF -- = ---------- = k AC 2S△ABC 由比例关系不难得出点H坐标Xh,Yh Xh = k(Xc-Xa) + Xa Yh = k(Yc-Ya) + Ya 再根据向量和的公式很容易可以求出G点坐标 Xg = Xh + Xb - Xa Yg = Yh + Yb - Ya Followed by: Post your reply here: |
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